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Exam Code: 1Z0-047

Exam Name: Oracle (Oracle Database SQL Expert)

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NO.1 View the Exhibit and examine the description of the EMPLOYEES table. You want to display the
EMPLOYEE_ID, FIRST_NAME, and DEPARTMENT_ID for all the employees who work in the same
department and have the same manager as that of the employee having EMPLOYEE_ID 104. To
accomplish the task, you execute the following SQL statement: SELECT employee_id, first_name,
department_id FROM employees WHERE (manager_id, department_id) =(SELECT department_id,
manager_id FROM employees WHERE employee_id = 104) AND employee_id <> 104; When you
execute the statement it does not produce the desired output. What is the reason for this?
A.The WHERE clause condition in the main query is using the = comparison operator, instead of EXISTS.
B.The WHERE clause condition in the main query is using the = comparison operator, instead of the IN
operator.
C.The WHERE clause condition in the main query is using the = comparison operator, instead of the =
ANY operator.
D.The columns in the WHERE clause condition of the main query and the columns selected in the
subquery should be in the same order.
Answer:D

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NO.2 EMPDET is an external table containing the columns EMPNO and ENAME. Which command would
work in relation to the EMPDET table?
A.UPDATE empdet SET ename = 'Amit' WHERE empno = 1234;
B.DELETE FROM empdet WHERE ename LIKE 'J%';
C.CREATE VIEW empvu AS SELECT * FROM empdept;
D.CREATE INDEX empdet_idx ON empdet(empno);
Answer:C

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NO.3 View the Exhibit and examine the structure of the EMP table which is not partitioned and not an
index-organized table. Evaluate the following SQL statement: ALTER TABLE emp DROP COLUMN
first_name; Which two statements are true regarding the above command? (Choose two.)
A.The FIRST_NAME column would be dropped provided it does not contain any data.
B.The FIRST_NAME column would be dropped provided at least one or more columns remain in the table.
C.The FIRST_NAME column can be rolled back provided the SET UNUSED option is added to the above
SQL statement.
D.The FIRST_NAME column can be dropped even if it is part of a composite PRIMARY KEY provided the
CASCADE option is used.
Answer:B D

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NO.4 View the Exhibit and examine the structure of the EMPLOYEES table. You want to retrieve hierarchical
data of the employees using the top-down hierarchy. Which SQL clause would let you choose the
direction to walk through the hierarchy tree?
A.WHERE
B.HAVING
C.GROUP BY
D.START WITH
E.CONNECT BY PRIOR
Answer:E

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NO.5 View the Exhibit and examine the data in ORDERS and ORDER_ITEMS tables. You need to create a
view that displays the ORDER ID, ORDER_DATE, and the total number of items in each order. Which
CREATE VIEW statement would create the view successfully?
A.CREATE OR REPLACE VIEW ord_vu (order_id,order_date) AS SELECT o.order_id, o.order_date,
COUNT(i.line_item_id) "NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id)
GROUP BY o.order_id,o.order_date;
B.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
"NO OF ITEMS" FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date;
C.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)
FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY o.order_id,o.order_date;
D.CREATE OR REPLACE VIEW ord_vu AS SELECT o.order_id, o.order_date, COUNT(i.line_item_id)||'
NO OF ITEMS' FROM orders o JOIN order_items i ON (o.order_id = i.order_id) GROUP BY
o.order_id,o.order_date WITH CHECK OPTION;
Answer:B

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NO.6 View the Exhibit and examine the structure of the MARKS_DETAILS and MARKStables. Which is the
best method to load data from the MARKS_DETAILStable to the MARKStable?
A.Pivoting INSERT
B.Unconditional INSERT
C.Conditional ALL INSERT
D.Conditional FIRST INSERT
Answer:A

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NO.7 View the Exhibit and examine the description of the CUSTOMERS table. You want to add a constraint
on the CUST_FIRST_NAME column of the CUSTOMERS table so that the value inserted in the column
does not have numbers. Which SQL statement would you use to accomplish the task?
A.ALTER TABLE CUSTOMERS ADD CONSTRAINT cust_f_name
CHECK(REGEXP_LIKE(cust_first_name,'