2014年1月14日星期二

Best Oracle 1Z0-805 exam questions and answers

If you're still studying hard to pass the Oracle 1Z0-805 exam, Pass4Test help you to achieve your dream. We provide you with the best Oracle 1Z0-805 exam materials. It passed the test of practice, and with the best quality. It is better than Oracle 1Z0-805 tutorials and any other related materials. It can help you to pass the Oracle 1Z0-805 exam, and help you to become a strong IT expert.

If you have decided to participate in the Oracle 1Z0-805 exam, Pass4Test is here. We can help you achieve your goals. We know that you need to pass your Oracle 1Z0-805 exam, we promise that provide high quality exam materials for you, Which can help you through Oracle 1Z0-805 exam.

Exam Code: 1Z0-805
Exam Name: Oracle (Upgrade to Java SE 7 Programmer)
One year free update, No help, Full refund!
Total Q&A: 90 Questions and Answers
Last Update: 2014-01-14

After the advent of the Pass4Test's latest Oracle certification 1Z0-805 exam practice questions and answers, passing Oracle certification 1Z0-805 exam is no longer a dream of the IT staff. All of Pass4Test's practice questions and answers about Oracle certification 1Z0-805 exam have high quality and 95% similarity with the real exam questions. Pass4Test is worthful to choose. If you choose Pass4Test's products, you will be well prepared for Oracle certification 1Z0-805 exam and then successfully pass the exam.

Pass4Test Oracle 1Z0-805 exam questions and answers provide you test preparation information with everything you need. About Oracle 1Z0-805 exam, you can find these questions from different web sites or books, but the key is logical and connected. Our questions and answers will not only allow you effortlessly through the exam first time, but also can save your valuable time.

The quality of Pass4Test product is very good and also have the fastest update rate. If you purchase the training materials we provide, you can pass Oracle certification 1Z0-805 exam successfully.

The selection of proper training material is a promising method to pass Oracle 1Z0-805 exam. No quality, no success. Pass4Test Oracle 1Z0-805 questions and answers consist of perfect exam simulations, real test questions and accurate test answers. Our Pass4Test Oracle 1Z0-805 test provides high-quality products and improves after-sales service. If you spend a lot of time catching up, the way you choose is wrong. What is more serious is that you may fail. Please trust our Pass4Test Oracle 1Z0-805 braindump. By selecting it, 100% guarantee to pass the exam.

1Z0-805 Free Demo Download: http://www.pass4test.com/1Z0-805.html

NO.1 Given the code fragment:
dataFormat df;
Which statement defines a new DataFormat object that displays the default date format for the UK
Locale?
A. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
B. df = DateFormat.getDateInstance (DateFormat.DEFAULT, UK);
C. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale.UK);
D. df = new DateFormat.getDataInstance (DataFormat.DEFAULT, Locale.UK);
E. df = new DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
Answer: C

Oracle practice test   1Z0-805   1Z0-805

NO.2 Given the code fragment:
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?
A. }catch (IOException | NoSuchFileException e) { System.out.println(e); }
B. } catch (IOException | IndexOutOfBoundException e) { System.out.println(e); }
C. } catch (Exception | IOException | FileNotFoundException e ) { System.out.println(e); }
D. } catch (NoSuchFileException e ) { System.out.println(e); }
E. } catch (InvalidPathException | IOException e) { System.out.println(e); }
Answer: B,D,E

Oracle exam prep   1Z0-805   1Z0-805 exam   1Z0-805

NO.3 Given the following code fragment:
public class Calc {
public static void main (String [] args) {
//* insert code here Line ** System.out.print("The decimal value is" + var);
}
}
Which three code fragments, when inserted independently at line **, enable the code to compile/
A. int var = 0b_1001;
B. long var = 0b100_01L;
C. float var = 0b10_01;
D. float var = 0b10_01F;
E. double var = 0b10_01;
F. double var = 0b10_01D;
Answer: B,C,E

Oracle test   1Z0-805 dumps torrent   1Z0-805 answers real questions   1Z0-805 pdf

NO.4 Given the code fragment: public class Test {
public static void main (String [] args) {
Path path1 = Paths.get("D:\\sys\\asm\\.\\data\\..\\..\\mfg\\production.log");
System.out.println(path1.normalize());
System.out.println(path1.getNameCount());
}
}
What is the result?
A. D:\sys\mfg\production.log 8
B. D:\\sys\\asm\\.\\data\\. . \\mfg\\production.log 6
C. D: \\sys\\asm\\.\\data\\. . \\mfg\\production.log 8
D. D: \sys\mfg\production.log 4
E. D: \\ sys\\asm\\data\\mfg\\production.log 6
Answer: A

Oracle   1Z0-805   1Z0-805 exam prep   1Z0-805 braindump   1Z0-805

NO.5 Which code fragments print 1?
A. String arr [] = {"1", "2", "3"}; List <? extendsString > arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
B. String arr [] = {"1", "2", "3"}; List <Integer> arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
C. String arr [] = {"1", "2", "3"}; List <?> arrList = new LinkedList <> (Arrays.asList (arr)); System.out.println
(arrList.get (0));
D. String arr [] = {"1","2","3"}; List <?> arrList = new LinkedList <?>(Arrays.asList (arr)); System.out.println
(arrList.get (0));
E. String arr [] = {"1","2","3"}; List <Integer> extendsString > arrList =new LinkedList <Integer>
(Arrays.asList (arr)); System.out.println (arrList.get (0));
Answer: A,C

Oracle   1Z0-805 practice test   1Z0-805 practice test

NO.6 Given the fragment:
public class CustomerApplication {
public static void main (String [] args) {
CustomerDAO custDao = new CustomerDAOMemoryImp1 ();
// . . . other methods
} }
Which two valid alternatives to line 3 would decouple this application from a specific implementation of
customerDAO?
A. CustomerDAO custDao = new customerDAO();
B. CustomerDAO custDao = (CustomerDAO) new object();
C. CustomerDAO custDao = CustomerDAO.getInstance();
D. CustomerDAO custDao = (CustomerDAO) new CustomerDAOmemoryImp1();
E. CustomerDAO custDao = CustomerDAOFactory.getInstance();
Answer: C,E

Oracle   1Z0-805 test   1Z0-805 practice test

NO.7 Which statement is true about the take method defined in the WatchService interface?
A. Retrieves and removes the next watch key, or returns null of none are present.
B. Retrieves and removes the next watch key. If a queued key is not immediately available, the program
waits for the specified wait time.
C. Retrieves and removes the next watch key: waits if no key is yet present.
D. Retrieves and removes all pending events for the watch key, returning a list of the events that were
retrieved.
Answer: C

Oracle test answers   1Z0-805 certification training   1Z0-805   1Z0-805   1Z0-805 questions

NO.8 Given the code fragment:
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the file info.txt to
the destination directory, even if a file by the same name already exists in the destination directory?
A. try {FileChannel in = new FileInputStream(source).getChannel(); FileChannel out = new
FileOutputStream(dest).getChannel (); in.transferTo (0, in.size(), out);
B. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
C. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
D. try {Files.move(Paths.get(source),Paths.get(dest));
E. try {BufferedReader br = Files.newBufferedReader(Paths.get(source), Charset.forName ("UTF8"));
BufferedWriter bw = Files.newBufferedWriter (Paths.get(dest), Charset.forName ("UTF-8")); String record
= ""; while ((record = br.readLine()) != null){ bw.write (record); bw.newLine(); }
Files.delete(Paths.get(source));
Answer: B,D

Oracle   1Z0-805   1Z0-805   1Z0-805 exam

NO.9 You are using a database from XY/Data. What is a prerequisite for connecting to the database using a
JDBC 4.0 driver from XY/Data?
A. Use the JDBC DriverManager.loadDriver method.
B. Put the XY/data driver into the classpath of your application.
C. Create an instance of the XY/Data driver class using the new keyword.
D. Create an Implementation of DriverManager that extends the XY/Data driver
Answer: B

Oracle pdf   1Z0-805 answers real questions   1Z0-805 practice test   1Z0-805 test questions   1Z0-805 exam simulations   1Z0-805 pdf

NO.10 Given three resource bundles with these values set for menu1: ( The default resource bundle is
written in US English.)
English US resource Bundle Menu1 = small
French resource Bundle Menu1 = petit
Chinese Resource Bundle Menu = 1
And given the code fragment:
Locale.setDefault (new Locale("es", "ES")); // Set default to Spanish and Spain loc1 = Locale.getDefault();
ResourceBundle messages = ResourceBundle.getBundle ("messageBundle", loc1); System.out.println
(messages.getString("menu1")); What is the result?
A. No message is printed
B. petit
C. :
D. Small
E. A runtime error is produced
Answer: E

Oracle test   1Z0-805 exam dumps   1Z0-805 demo

NO.11 Given:
import java.util.*; public class StringApp { public static void main (String [] args) { Set <String> set = new
TreeSet <> (); set.add("X"); set.add("Y"); set.add("X"); set.add("Y"); set.add("X"); Iterator <String> it =
set.iterator (); int count = 0; while (it.hasNext()) { switch (it.next()){ case "X": System.out.print("X "); break;
case "Y": System.out.print("Y "); break; } count++; } System.out.println ("\ncount = " + count); } }
What is the result?
A. X X Y X Y count = 5
B. X Y X Y count = 4
C. X Y count = s
D. X Y count = 2
Answer: D

Oracle questions   1Z0-805 braindump   1Z0-805 exam   1Z0-805   1Z0-805 answers real questions   1Z0-805 test answers

NO.12 Which two statements are true about the walkFileTree method of the files class?
A. The file tree traversal is breadth-first with the given FileVisitor invoked for each file encountered.
B. If the file is a directory, and if that directory could not be opened, the postVisitFileFailed method is
invoked with the I/O exception.
C. The maxDepth parameter s value is the maximum number of directories to visit.
D. By default, symbolic links are not automatically followed by the method.
Answer: C,D

Oracle pdf   1Z0-805   1Z0-805   1Z0-805

NO.13 What design pattern does the Drivermanager.getconnection () method characterize?
A. DAO
B. Factory
C. Singleton
D. composition
Answer: B

Oracle questions   1Z0-805 pdf   1Z0-805 dumps   1Z0-805 test questions

NO.14 Given the code fragment:
List<Person> pList = new CopyOnWriteArrayList<Person>();
Which statement is true?
A. Read access to the List should be synchronized.
B. Write access to the List should be synchronized.
C. Person objects retrieved from the List are thread-safe.
D. A Person object retrieved from the List is copied when written to.
E. Multiple threads can safely delete Person objects from the List.
Answer: C

Oracle   1Z0-805   1Z0-805   1Z0-805

NO.15 Given a resource bundle MessageBundle, what is the name of the default bundle file?
A. MessageBundle.profile
B. MessageBundle.xml
C. MessageBundle.java
D. MessageBundle.properties
Answer: D

Oracle test answers   1Z0-805 questions   1Z0-805   1Z0-805   1Z0-805 dumps torrent

Pass4Test offer the latest HP0-J64 exam material and high-quality 1Y0-A26 pdf questions & answers. Our ICBB VCE testing engine and 3103 study guide can help you pass the real exam. High-quality NS0-504 dumps training materials can 100% guarantee you pass the exam faster and easier. Pass the exam to obtain certification is so simple.

Article Link: http://www.pass4test.com/1Z0-805.html

没有评论:

发表评论